Question

Find the value of k if the quadratic equation ( k - 4 )x² + 2( k - 4 )x + 4 = 0 has real and equal roots.​

Answer 1

Answer:

Step-by-step explanation:

ARE YOU FAMILIAR WITH THE DISCRIMINANT?

IF DISCRIMINANT EQUALS ZERO, ROOTS ARE REAL AND EQUAL.

D=SQT of B^2 - 4AC

THEN

B=4(X-4)

A=K-4

C=4

CONVERT TO THE FORMULA OF D=SQT of B^2-4AC

YOU WILL GET K=8

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Answer 2

Answer:

heya✌✌

Step-by-step explanation:

For equal roots it must have D=0 where D= b^2-4ac (b square minus 4ac)

or, b^2-4ac=0

or, (k+1)^2-4(k+4)(1)=0

or, k^2+2k+1-4k-4=0

or, k^2-2k-3=0

or, k^2-3k+k-3=0

or, k(k-3)+1(k-3)=0

or, k-3=0 and k+1=0

Hence the value of k should be 3 or -1.

Hope it helped.

Hope it helped.plss mark brainliest