Find the value of K if the quadratic equation x²+3kx+k+7=0 has equal Root
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since p(x) = 0 therefore b² =4ac
so
9k² = 4×1×(k+7)
9k²= 4k+28
9k²-4k-28=0
bro this question is wrong
so
9k² = 4×1×(k+7)
9k²= 4k+28
9k²-4k-28=0
bro this question is wrong
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hope this will help u out
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