Question

Find the value of k if the quadratic equation x2 - kx + 20 = 20 has real roots

Answer 1

Solution :

Compare x²-kx+20=0 with

ax²+bx+c = 0 we get,

a = 1 , b = -k, c = 20

Discreminant (D) > 0

[ Given , roots are real ]

b² - 4ac > 0

=> (-k)² - 4×1×20 > 0

=> k² - 80 > 0

=> k² > 80

=> k > ± √80

=> k > ± 4√5

••••

Answer 2

Answer:

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