find the value of k if the remainder is -3 when k x cube + 8 x square - 4 x + 10 is divided by X + 1
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Answer:
Let f(x) = kx^3 +8x^2-4x+10
If, g(x) = x+1,then. x=-1
Step-by-step explanation:
by putting this value of.x.in the above equation,
k(-1) + 8(1) - 4 + 10 = -3
-k + 8 - 4 + 10 = -3
transposing the whole numbers to RHS
-k = -8 +4 -10 -3
-k = -4 -13
-k=-17
Cancelling minus from both sides,
k = 17
The correct value of k is 17
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