find the value of k if the roots of equation (k²+2)x²+7x+3k=0 are the resiprocals of each other.
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Here is your answer:
Given that.
1) An expression kx² + 3x + 5.
2) The roots are reciprocal of each other.
To find,
The value of k.
Solution:
Let the roots be : \alpha \ and \ \frac{1}{ \alpha }α and
α
1
Then, We know that,
Product\ of\ roots = \frac{c}{a}Product of roots=
a
c
Here c = 5 & a = k
Then,
⇒ \alpha \times \frac{1}{ \alpha } = \frac{5}{k}α×
α
1
=
k
5
⇒ 1 = \frac{5}{k}1=
k
5
⇒ k = 5.k=5.
Therefore the value of k is 5.
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Hope my answer is helpful to you.
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