Question

Find the value of k, if the roots of quadratic equations
3x² – kx+48=0 are real and e.​

Answer 1

Answer:

3x² - k√3 x + 4 =0comparegivenquadraticequation3x²−k√3x+4=0

with \: \: ax² + bx + c = 0 ,withax²+bx+c=0,

a = 3 , b = - k√3 , c = 4a=3,b=−k√3,c=4

given ,accordingtotheproblemgiven,

rootsareequal.

b² = 4ac b²=4ac

( - k√3 )² = 4 × 3 × 4(−k√3)²=4 ×3 ×4

k² × 3 = 4 ×3 × 4k²×3=4 ×3 ×4

k² = 4 × 4k²=4 ×4

k = √ 4 × 4k= √4 ×4

k = 4 or k = -4 k=4ork=−4

Step-by-step explanation:

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Answer 2

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