Question

Find the value of k, if the roots of the quadratic equation 2×2-6×+k=0 are real and equal​

Answer 1

Answer:

2

Step-by-step explanation:

2×2-6×+k=0

4-6×+k=0

-2×+k=0

+k=0+2

k=2

Answer 2

Answer:

9

Step-by-step explanation:

Comparing the question with ax²+by+c=0, we get,

a=1; b=-6; c=k

b2-4ac=0

(-6)²-4×1×k=0

36-4k=0

36=4k

k=9 (4×9=36)