Question

find the value of K if the roots of the quadratic equation 3x^2--kx+48=0. are real and equal .​

Answer 1

Answer:

k=24 is your answer

Step-by-step explanation:

a=3 b=k c=48

b^2 -4ac =0

k^2 -4*3*48=0

k^2 -12*48=0

k^2-576 =0

k^2=576

k=√576

k=24

Answer 2

Given,

The quadratic equation: 3x²-kx+48 = 0

To find,

The value of k if the roots are equal and real.

Solution,

We can easily solve this problem by following the given steps.

According to the question,

We have the following quadratic equation:

3x²-kx+48 = 0

Now, we know that if the roots are real and equal then the value of the determinant (D) is zero.

D = $\sqrt{ {b}^{2} - 4ac}$$\sqrt{ {b}^{2} - 4ac}$ = 0

b² = 4ac

In this case, we have a = 3, b = -k and c = 48.

(-k)² = 4(3)(48)

k² = 12(48)

k² = 576

k =√576

k = ±24

Hence, the value of k is ± 24.