Question

Find the value of k if the roots of the quadratic equation 2x²-6x+k=0
real and equal​

Answer 1

Step-by-step explanation:

condition for a quadartic equation to be real and equal is...

$b {}^{2} - 4ac = 0$

so

a quadratic equation is expressed as

$ax {}^{2} + bx + c = 0$

so here

a=2

b=-6

c=k

so

now,

substituting in formula

$( - 6) {}^{2} - 4(2)(k) = 0$

36-8k=0

=> 8k = 36

=> k=36/8

=> k=9/2

i think this is the answer...

pls cross verify..

hope it helps