Question

Find the
value of K, if the
roots of the
quadratic equation
equation " 3x2 - "Kx + 48= 0
are real
and equal​

Answer 1

Step-by-step explanation:

p(x)= 3x²-Kx+48

a= 3, b= -K, c=48

Since, it has real and equal roots

So, D=0

b²- 4ac= 0

(-K)²-4(3)(48)=0

K²-576=0

K²=576

K=√576

Hence, K= 24

I hope it will help you