Math, asked by balaji09870, 8 months ago

Find the value of k, if the rots of tge quadretic equation 2x square- 6x+k=0 are real and equal​

Answers

Answered by milindingle1968
0

Answer:

Discriminant(b^2 - 4ac) of Quadratic equation is zero. 2x2- 6x + k = 0, the roots of are real and equal. Therefore Discriminant of Quadratic equation is zero.

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Answered by aryan073
1

Step-by-step explanation:

2x²-6x+k=0

b²-4ac

36-4(2)(k)

36-8k=0

k=36/8=18/4=9/2

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