Question

find the value of k if the slope of the line joining the points 3,-4 & k,2 is -3​

Answer 1

Step-by-step explanation:

I hope this will help you

Answer 2

Therefore the value of k is 1

Step-by-step explanation:

Given points are (3,-4) and (k,2)

The slope of a line joining by two points (x₁,y₁) and (x₂,y₂) is

$=\frac{y_2-y_1}{x_2-x_1}$

Here x₁=3 ,y₁= -4, x₂= k and y₂= 2

Therefore the slope of the line by joining (3,-4) and (k,2) is $\frac{2-(-4)}{k-3}$

                                                                                                 $=\frac{6}{k-3}$

According to the problem,

$\frac{6}{k-3}=-3$

⇒6= -3(k-3)

⇒6 = -3k+9

⇒ -3k = 6-9

⇒ -3k = -3

⇒k=1

Therefore the value of k is 1