Question

Find the value of k, if the solution of the equation 2² + 3 = k is (2,1).​

Answer 1

Step-by-step explanation:

$\sf \leadsto 2 {x}^{2} + 3y = k \\ \sf \leadsto 2 {(2)}^{2} + 3(1) = k \\ \sf \leadsto 2(4) + 3 = k \\ \sf \leadsto k = 8 + 3 \\ \sf \leadsto k = 11$