find the value of k ,if the straight lines y-3kx+4=0 and (2k-1)x-(8k-1)y-6=0 are perpendicular
Answers
Answered by
18
Given lines are -3kx + y + 4 = 0
(2k – 1)x – (8k – 1)y – 6 = 0
These lines are perpendicular
a1b2-a2b1
3k(2k 1) 1(8k 1) 0 6k 3k 8k 1 0
6k 5k 1 0 (k 1)(6k 1) 0 k 1
or 1/6
(2k – 1)x – (8k – 1)y – 6 = 0
These lines are perpendicular
a1b2-a2b1
3k(2k 1) 1(8k 1) 0 6k 3k 8k 1 0
6k 5k 1 0 (k 1)(6k 1) 0 k 1
or 1/6
Answered by
3
Step-by-step explanation:
hope it helps...
plss mark me as brainlilest.....
Attachments:
Similar questions