Question

find the value of k if the sum of the zeros of the polynomial of x square + kx + 10 is 12​

Answer 1

sum of zeros = -( coefficient of x)/(coefficient of x^2)

=> 12 /1= -( coefficient of x)/(coefficient of x^2)

=> cefficient of x= -12

k = -12..

$<marquee> ..k= -12..mark brainliest$

Answer 2

GIVEN:

→$A\:polynomial\:x^{2}+kx+10$

→The sum of zeroes is 12.

TO FIND:

→The value of k.

ANSWER:

We know in a quadratic equation of $ax^{2}+bx+c$ form,

The sum of zeroes is given by, say $\alpha \:and\:\beta$ is given by,

$\large\green{\boxed{\alpha+\beta=\dfrac{(-b) }{a}}}$

Here $\alpha+\beta=12$

On substituting the values,

=>$\dfrac{-b}{a} = \alpha+ \beta$

=>$\dfrac{-k}{1}=12$

$\large\red{\boxed{\alpha+\beta=12}}$

=>$-k = 12×1$

=>$k =-12$

Therefore the value of k should be -12.

$\huge\orange{\boxed{k \:\:=\:\:(-12) }}$