Question

Find the value of k if the system has infinite solutions:
2x-3y=7
(K+2)x - (2x+1)y = 3(2k-1)

Answer 1

Answer:

k=4

Step-by-step explanation:

2x-3y-7=0

(K+2)x-(2k+1)y-3(2k-1)=0

for infinite solution:

(k+2)/2=-(2k+1)/-3=-3(2k-1)/-7

(k+2)/2=2k+1/3=6k-3/7

So 3*(k+2)=2*(2k+1)

3k+6=4k+2

k=6-2=4

k=4