Question

Find the value of k if the system of equation has no solution

x + ky = 10
6x + 36y = 4

Answer 1

Answer:

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Step-by-step explanation:

so here given linear equations are x + ky = 10 and 6x + 36y = 4

so comparing these both equations with

a1x+b1y=c1 and a2x+b2y=c2

we get

a1=1 a2=6 b1=k b2=36 c1=10 c2=4

so as the given equations have no solution ie have infinitely many solutions

a1/a2=b1/b2=c1/c2

1/6=k/36=10/4

considering thus

1/6=k/36

ie 1=k/6

ie k=6

hence value of k is 6