Question

Find the value of k if the system of linear equation
3x-4y+7=0
Kx+3y-5=0
has no solutions

Answer 1

Answer:

Answer is option 2 -9/4

Step-by-step explanation:

hi

Answer 2

Answer:

The value of  k is - 9 / 4 for the system of equations 3 x - 4 y + 7 = 0 and K x + 3 y - 5 = 0 having no solution.

Step-by-step explanation:

If a system of linear equations has no solution, then it should satisfy the condition:

(a₁ / a₂) = (b₁ / b₂) ≠ (c₁ / c₂).

We have the two equation:

3 x - 4 y + 7 = 0

K x + 3 y - 5 = 0

Here,

a₁ = 3

a₂ = K

b₁ = - 4

b₂ = 3

c₁ = 7

c₂ = - 5.

Applying the condition:

3 / K = - 4 / 3 ≠ 7 / -5

We get that:

3 / K = - 4 / 3

9 = - 4 K

K = - 9 / 4.

Therefore, the value of  k is - 9 / 4.

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