Find the value of k if the zero of the polynomial p(x)=x2^+KX-10 is 3
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Answered by
7
if 3 is the zero of polynomial the polynomial then,
⇒x^2+kx-10
⇒(3)^2+k(3)-10=0
⇒9+3k-10=0
⇒3k=10-9
⇒3k=1
⇒k=1/3
∴ the value of k = 1/3
i hope that this will help u........................^_^
⇒x^2+kx-10
⇒(3)^2+k(3)-10=0
⇒9+3k-10=0
⇒3k=10-9
⇒3k=1
⇒k=1/3
∴ the value of k = 1/3
i hope that this will help u........................^_^
Answered by
2
if 3 is a zero of p(x) = x²+kx-10
p(3) = 0
⇒ 3²+k×3-10 = 0
⇒ 9+3k-10 = 0
⇒ 3k-1=0
⇒ k = 1/3
p(3) = 0
⇒ 3²+k×3-10 = 0
⇒ 9+3k-10 = 0
⇒ 3k-1=0
⇒ k = 1/3
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