Question

Find the value of k if the zeroes of the polynomial
$k {x}^{2} - 10x + 2(k + 1)$
are
$\alpha \: and \: \beta$
and
$3 \alpha + 2 \beta = 8$
​

Answer 1

Answer:

Hey there

So let's solve your your problem step by step.

We know that

(a+b)^2=a^2 + b^2 + 2ab.

So

We already have values for LHS as 5 and value of ab as 3.

So,

(a+b)^2 =5^2 = 25

And, 2ab = 2*3 = 6

Now we substitute the values for both in general equation and we get,

25 = a^2 + b^2 + 6

a^2 + b^2 = 25 -6 = 19.

Therefore, the answer to your question is 19.

Answer 2

Answer:

Analysis shows that nickel oxide has the formula ni0.98 o1.00. What fractions of nickel exist as ni2+ and ni3+ ions?