Question

find the value of k if x=1/2√3 is zero of polynomial p(x)=2kx^2-7x+k

Answer 1

x=1/2root3
=2root3/2root3×2root3
=2root3/ 12
=root3/6
p(x)=2kx^2-7x+k
p(root3/6)=2×k×(root3/6)^2-7 (root3/6)+k
=2k×3/36-7root3+k
=k/6-7root3/6+k
=k-7root3+6k/6=0
=k-7root3+6k=0×6=0
=7k=7root3
=k=7root3/7
=k=root3

Answer 2

X=1/2root3

=2root3/2root3×2root3

=2root3/ 12

=root3/6

p(x)=2kx^2-7x+k

p(root3/6)=2×k×(root3/6)^2-7 (root3/6)+k

=2k×3/36-7root3+k

=k/6-7root3/6+k

=k-7root3+6k/6=0

=k-7root3+6k=0×6=0

=7k=7root3

=k=7root3/7

=k=root3

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