Question

Find the value of k if x=-1/2 is one root of a quadratic equation 2x^2 +Kx+1=0

Answer 1

Answer:

Step-by-step explanation:

2x^2 + kx +1 = 0

Now -1/2 is a root of the equation so it will satisfy the equation.

Put -1/2 in an equation.

2(-1/2)^2 + k(-1/2) + 1 = 0

2 / 4 - 1/2k + 1= 0

1/2 - 1/2k + 1 = 0

3/2 - 1/2k = 0

-1/2k = -3/2

k = 3

Answer 2

Answer:

k=?

x=-1/2

0=2(-1/2)²+k(-1/2)+1

0=2/4-k/2+1

0=1/2-k/2+1

1+1/2=k/2

3/2=k/2

k=6/2=3

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