Math, asked by tanishdhillon260, 7 hours ago

find the value of k if x-1 factor of 2ײ+Kx+√2​

Answers

Answered by jyotidevi2393
0

g(x) = x-1

x = 1

p(x) = 2x² + kx + √2

2(1)² + k(1) + √2 =0

2+ √2 + k = 0

k = -(2+√2)

hope it helps

Answered by stunivashini868
0

Answer:

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Class 9

>>Maths

>>Polynomials

>>Factorisation of Polynomial

>>Find the value of 'a' if (x - 2) is fact

Question

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Find the value of 'a' if (x-2) is factor of 2x

3

−6x

2

+5x+a.

Medium

Solution

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Correct option is C)

Let p(x)=2x

3

−6x

2

+5x+a and

g(x)=x−2

=>x−2=0

=>x=2

If g(x) is a factor of p(x), then p(2) should be equal to zero.

p(2)=2x

3

−6x

2

+5x+a=0

=>2(2)

3

−6(2)

2

+5(2)+a=0

=>16−24+10+a=0

=>2+a=0

=>a=−2

Step-by-step explanation:

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