find the value of k if x-1 factor of 2ײ+Kx+√2
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g(x) = x-1
x = 1
p(x) = 2x² + kx + √2
2(1)² + k(1) + √2 =0
2+ √2 + k = 0
k = -(2+√2)
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Class 9
>>Maths
>>Polynomials
>>Factorisation of Polynomial
>>Find the value of 'a' if (x - 2) is fact
Question
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Find the value of 'a' if (x-2) is factor of 2x
3
−6x
2
+5x+a.
Medium
Solution
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Correct option is C)
Let p(x)=2x
3
−6x
2
+5x+a and
g(x)=x−2
=>x−2=0
=>x=2
If g(x) is a factor of p(x), then p(2) should be equal to zero.
p(2)=2x
3
−6x
2
+5x+a=0
=>2(2)
3
−6(2)
2
+5(2)+a=0
=>16−24+10+a=0
=>2+a=0
=>a=−2
Step-by-step explanation:
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