Question

Find the value of k if x-1 is a factor is x² +kx + √2
plz guys I need is rlly quick!!!!​

Answer 1

Answer:

k = -( root2 + 2)

Step-by-step explanation:

2x2+kx+2

2+k+2=0

k=−(root2+2) 

Answer 2

Step-by-step explanation:

Given : x-1 is a factor of x^2 +kx +√2

To find: value of k

Solution:

If (x-1) is a factor of x^2 +kx +√2

then it will

x-1=0

and x=1 will satisfy the equation

x^2 +kx +√2=0

(1)^2 + k(1)+√2=0

1+k+√2=0

k= -(√2+1)

This implies k= -(√2+1)