find the value of k if x-1 is a factor of 2 K x²-2√2x
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Answer:
2KX²-2√2x.
x-1=0.
x=1.
2K(1)²-2√2(1).
2K(1)-2√2.
2K-2√2.
2K=2√2.
K=2√2/2.
K=√2.
I think this is your answer.
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