Question

find the value of k if (x-1) is a factor of 2x^2+kx+root 2​

Answer 1

Answer:minus two minus root two

Step-by-step explanation:sub 1 in the equation and equate to 0 as x-1 is a factor

Answer 2

The value of k is $-\sqrt{2}(\sqrt{2}+1)$.

Step-by-step explanation:

The expression is:

$2x^{2}+kx+\sqrt{2}=0$

One of the factors of the equation is (x - 1).

That is, x = 1 will satisfy the equation.

Substitute x = 1 in the equation and compute the value of x as follows:

    $2x^{2}+kx+\sqrt{2}=0$

$2(1)^{2}+k(1)+\sqrt{2}=0$

          $k+2+\sqrt{2}=0$

   $k+\sqrt{2}(\sqrt{2}+1)=0$

                          $k=-\sqrt{2}(\sqrt{2}+1)$

Thus, the value of k is $-\sqrt{2}(\sqrt{2}+1)$.

Learn more:

https://brainly.in/question/5412549