Question

find the value of k , if x -1 is a factor of 3x^2 + 5x^2 - 6x + k​

Answer 1

Answer:

-2

Step-by-step explanation:

by factor theorem substituting x=1

f(1)= 3+5-6(1)+k=0

k=-2

Answer 2

Given:

• Find the value of k, if x-1 is a factor of 3x²+5x²-6x+k.

To find:

• Value of k

Solution:

$: \implies \sf{x - 1 = 0}$

$: \implies \sf{x = 0 + 1}$

$: \implies   \underline{\boxed{ \frak{x = 1}}} \blue \bigstar$

• Let's find the value of k

$: \implies \sf{ {3x}^{2} + {5x}^{2} - 6x + k = 0}$

• Now, put the value of x

$:\implies\sf{{3(1)}^{2}+ {5(1)}^{2}-6(1)+ k=0}$

$:\implies \sf{ {3(1) + {5(1)} - 6(1)+ k = 0}}$

$:\implies \sf{ {3 + {5} - 6+ k = 0}}$

$:\implies \sf{ {8 - 6+ k = 0}}$

$:\implies \sf{ {2+ k = 0}}$

$:\implies \sf{ {k = 0 - 2}}$

$: \implies   \underline{\boxed{ \frak{k = ( - 2)}}} \pink \bigstar$

• Hence, the value of k is (-2)

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