Question

Find the value of k, if (x + 1) is a factor of a polynomial, kx cube - 9x square + x + 6k

Answer 1

Answer:

If (x+1) is factor then x = –1 is one zeros of polynomial. so putting x = -1 in polynomial. we get,

$k( - 1) {}^{3} - 9( - 1) {}^{2} - 1 + 6k = 0 \\ - k - 9 - 1 + 6k = 0 \\ 5k = 10 \\ k = 2 \\ ans.$

Answer 2

Please see the attachment

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