Question

Find the value of K if (x-1)is a factor of g(x)=kx2+6x-3k.

Answer 1

Answer:

x=1

ɢ(1) = ᴋ.1^2 + 6.1 - 3.ᴋ

= ᴋ + 6 - 3ᴋ

= 2ᴋ + 6

= 2 ᴋ = -6

= ᴋ = -3

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs

Answer 2

Answer:

Step-by-step explanation:

It is given that (x-1) is a factor of g(x) so if we divide it then the answer should be 0.

$x-1 = 0\\x=1$

put x = 1

$k(1)^{2} + 6(1) + 3k = 0\\k + 6 + 3k = 0\\4k=-6\\k= \frac{-6}{4} \\k= \frac{-3}{2}$