Question

find the value of k if x-1 is a factor of kx2 - root (2) x +1​

Answer 1

Answer:

$p(x) = k {x}^{2} - \sqrt{2x} + 1$

$x - 1 = 0$

$x = 1$

$p(1) = k {1}^{2} - \sqrt{2 \times 1} + 1 = 0$

$k - \sqrt{2} + 1 = 0$

$k - \sqrt{2} = - 1$

$k = - 1 + \sqrt{2}$

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