Question

find the value of K if (x-1) is a factor of kx³+3x²-4x+k ​

Answer 1

Answer:

Step-by-step explanation:

p(x)=4x³+3x²-4x+k=0

(x-1) is a factor of p(x)

x = 1

p(1)=4(1)^3+3(1)^2-4(1)+k=0

=4+3-4+k=0

=. k = -3

Answer 2

Answer:

$k = \frac{1}{2}$

Step-by-step explanation:

$x - 1 = 0 \\ x = 1 \\ \\ k {x}^{3} + 3 {x}^{2} - 4x + k = 0 \\ k {(1)}^{3} + 3 {(1)}^{2} - 4(1) + k = 0 \\ k + 3 - 4 + k = 0 \\ 2k - 1 = 0 \\ k = \frac{1}{2}$