Question

Find the value of K if x-1 is a factor of p(x)=2x^2+Kx+under root 2.

Answer 1

given x- 1 is the factor of the given

polynomial p(x) = 2x² +kx +√2

so p(x) = 0

2(-1)² + k(-1) +√2 = 0

-k +2 +√2 = 0

k = 2+√2

HOPE ITS HELP U

Answer 2

Answer:

Given factor :- x-1

Putting x = 1

${2x}^{2} + kx \sqrt{2}$=0

2(1)^2 + k (1)√2 =0

k => 2+√2