Question

find the value of 'K' if (X+1) is a factor of p(X)=2x+Kx+√2​

Answer 1

Answer:

k= -2+√2

Step-by-step explanation:

x = -1

p(-1) = -2-k+√2

k = -2+ √2

Answer 2

Step-by-step explanation:

$x + 1 = 0 \\ x = - 1$

$2x + kx + \sqrt{2} \\ = 2( - 1) + k( - 1) + \sqrt{2} \\ = - 2 - k + \sqrt{2}$

$- 2 - k + \sqrt{2} = 0 \\ k = - 2 + \sqrt{2} \\ k = \sqrt{2} (1 - \sqrt{2} )$