Question

find the value of k if x-1 is a factor of p(x)= 2x² + kx+√2
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Answer 1

Step-by-step explanation:

x-1 is factor of p(x).

x-1=0

x=1

p(x)= 2x^2 + kx+ √2

p(1)= 2(1)^2 + k(1) + √2= 0

2+k+√2= 0

k= 2-√2

k= √2(√2-1)

Answer 2

x - 1 = 0

x = 1

p ( x ) = 2x^2 + kx + √2

p ( 1 ) = 2 ( 1 ) ^ 2 + k 1 + √2

p ( 1 ) = 2 +1 k +√2

k = 3√2