Question

find the value of k if x-1 is a factor of p(x) in each of the following case p(x)=kx^2✓2^x+1​

Answer 1

Answer:

Step-by-step explanation:

Hey

p(x)=kx^2-√2x+1

g(x)=x+2=>x=-2

Thus,

p(x)=p(-2)

=>p(-2)=k(-2)^2-√2(-2)+2

=>4k+2√2+2=0

=>2k+√2+1=0

=>2k=-(√2+1)

=>k= -(√2-1)/2

Answer 2

Answer:

Step-by-step explanation:

p(x)=kx^2-√2x+1

g(x)=x+2=>x=-2

Thus,

p(x)=p(-2)

=>p(-2)=k(-2)^2-√2(-2)+2

=>4k+2√2+2=0

=>2k+√2+1=0

=>2k=-(√2+1)

=>k= -(√2-1)/2