Question

find the value of k, if x-1 is a factor of p(x) in each of the following cases :
p(x) = 2x^2+Kx+√2​

Answer 1

Answer:

2+k+root 2

hope it helps

Answer 2

Given :

• p(x) = 2x² + Kx + √2
• x-1 is a factor of p(x)

To find :

Value of K

Solution :

Let , g(x) = x-1

Now for g(x) = x-1 , to be factor of p(x) = 2x² + Kx + √2 we will put g(x) = 0 and will find the value of x . and than we will put that value of x in p(x) and will equate it with zero, that is ,p(x) = 0

➝ g(x) = x-1 = 0

➩ x = 1

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➝ p(1) = 2(1²) + K(1) + √2

➩ 0 = 2(1) + K + √2

➩ 0 = K + 2+√2

➩ K = -2 - √2

➩ K = -(2+√2)

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ANSWER : -(2+√2)