Question

Find the value of k, if x-1 is a factor of p(x) in each of the following cases:
(1) P(x)=X2 +x +k
(ii) p(x) = 2 x2 + kx + ✓2
(ii) p(x) = kx2- √2x + 1
(iv) p(x) = kx2 – 3x +k
​

Answer 1

Answer:

if x-1=0

x=1

1)p(x)=x²+x+k

=(1)²+(1)+k

=1+1+k

=2k

k=-2

ii)p(x)=2x²+kx+√2

=2(1)²+k(1)+√2

=2+k+√2

=2√2k

k=-2√2

iii)p(x)=kx²-√2x+1

=k(1)²-√2(1)+1

=k-√2+1

k=1√2

iv)p(x)=kx²-3x+k

=k(1)²-3(1)+k

=k-3+k

=2k-3

2k =3

k=3/2

that is the answer of all question