Question

Find the value of K , if x-1 is a factor of P(x) in each of the following cases :

P(x) = 2x² + Kx + √2​

Answer 1

Answer:

x-1 is a factor of p(x) so p(1) = 0 by factor theorem

so 2x1 square + k + root2 =0

so k = -2-root2

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