Question

Find the value of k, if x – 1 is a factor of p(x) in p(x) = kx^2-√2x+1

Answer 1

Answer:

$\boxed{k=\sqrt{2}-1}$

Step-by-step explanation:

$p(x)=kx^2-\sqrt{2}x+1 \\\\ x-1 \ is \ a \ factor \\ =>x-1=0\\=>x=+1 \\\\ Put \ x=1,\\ kx^2-\sqrt{2}x+1=0 \\ k(1)^2-\sqrt{2}(1)+1=0 \\ k-\sqrt{2}+1=0 \\ k=\sqrt{2}-1$

Answer 2

Given x-1 is a factor

x-1=0

x=1

Put x=1

k(1)^2-√2+1=0

k-√2+1=0

k=√2-1