find the value of k, if x+1 is a factor of p(x) in the following :p(x) 2xsquare +kx + root 2
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Step-by-step explanation:
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Answer:
zero of the (x+1)
(x+1)=0
x=-1
put x = -1 in p(x)
p(x) = 2x²+kx+√2
= 2(-1)²+k(-1)+√2
= 2+k+√2
k = -2-√2
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