Question

find the value of k if x-1 is a factor of p(x) =kx^2- root 2 x+3​

Answer 1

Answer:

x-1=0

x=1

p(x)=0

Putting x=1 in p(x)=kx²-2√2x+3

k(1)²-2√2×1+3=0

k-2√2+3=0

k=2√2-3.

Hence the value of k = 2√2-3.

Answer 2

$\bf \huge \underline {\underline{SOLUTION}}$

p(x) = kx² - √2x + 1 p(1) = 0

k (1)² - √2(1) +1 = 0

=> k - √2 + 1 = 0

=> k = √2 - 1

Therefore the value of k is √2 - 1..

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