Question

Find the value of k, if x-1 is a factor of p(x) = kx2- √2x+1.​

Answer 1

Answer:

hii

user

here's ur answer

hope this hepls u....

Answer 2

If x-1 is a factor of the above equation then X=1

$k {x}^{2} - \sqrt{2} x + 1 = 0 \\ k {1}^{2} - \sqrt{2} (1) + 1 = 0 \\ k - \sqrt{2} + 1 = 0 \\ k = \sqrt{2} - 1$

Hope It Helps..........