Question

Find the value of k, if x–1 is a factor of p(x) = kx²–√2x+1​

Answer 1

Answer:

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Step-by-step explanation:

p(x) = kx² - √2x + 1

Now x - 1 is a factor

x - 1 = 0

x = 1

Now put x = 1 in p(x)

p(1) = 0

p(1) = k(1)² - √2(1) + 1 = 0

k - √2 + 1 = 0

k = √2 - 1

So required value of k = √2 - 1

Hope This Helps You!

Answer 2

Answer:

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Step-by-step explanation:

First Find the value of x

x-1=0

x=1

k×1²-√2×1+1

k×1-0×1+1

1k-1+1

1k-1

k=-1/1

k=0