Question

Find the value of K, if(x-1) is a factor
of p (x) = kx² - √2x + 1

Answer 1

Answer:

√2 - 1

Step-by-step explanation:

(x-1) = 0

X = 1

if(x-1) is a factor of p (x) = kx² - √2x + 1

so p(1) = o (by factor theorem)

p(1) = k(1)^2 - √2(1) + 1 = 0

k - √2 + 1 = 0

k = √2 - 1