Question

find the value of k,if (x-1) is a factor of p(x) =kx²-3x+k​

Answer 1

Answer:

The answer is $k=\frac{3}{2}$

Step-by-step explanation:

Concept : If $x-a$ is a factor of a polynomial $P(x)$, then $P(a)=0$

Here given $x-1$ is factor of $P(x)=kx^2-3x+k$

    $\Rightarrow P(1)=0\\\Rightarrow k(1)^2-3(1)+k=0\\\Rightarrow k-3+k=0\\\Rightarrow 2k=3\Rightarrow k=\frac{3}{2}$