Question

find the value of k , if x+1 is a factor of p(x) = kx²_x_4?​

Answer 1

Step-by-step explanation:

x+1 is the factor

so x=-1

kx²-x-4

substitute x=-1

k(-1)²-(-1)-4=0

k+1-4=0

k-3=0

k=3

Answer 2

Answer:

If x−1 is the factor of the equation then put x=1 in these equation  

(i) x  

2

+x+k=0⇒(1)  

2

+1+k=0⇒1+1+k=0⇒k=−2

(ii) 2x  

2

+kx+  

2

​  

=0⇒2(1)  

2

+k(1)+  

2

​  

=0⇒2+k+  

2

​  

=0⇒k=−2−  

2

​  

 

(iii) kx  

2

−  

2

​  

x+1=0⇒k(1)  

2

−  

2

​  

(1)+1=0⇒k−  

2

​  

+1=0⇒k=  

2

​  

−1

(iv) kx  

2

−3x+k=0⇒k(1)  

2

−3(1)+k=0⇒k−3+k=0⇒2k=−3⇒k=−  

2

3

​