Find the value of k if x-1 is a factor of p(x).
P(n)=x square +x+k
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According to the Question
p(x) = kx² - 3x + k
If (x - 1) is a factor of p(x)
Therefore
x - 1 = 0
x = 1
Substitute the value of x in Equation
⇒ k(1)² - 3 × 1 + k = 0
⇒ 2k - 3 = 0
⇒ 2k = 3
⇒ k =
Step-by-step explanation:
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