find the value of K if x-1 is a factor of p(x)p (x) = x²x+k
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the zero of the polynomial of x-1 is 1
so we put value of x as 1
so,
p(x)=x²x+K
p(1)=1²*1+K
0=1+K
-1=K
I think this the correct answer
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