Question

Find the value of K, if x-1 is a factor of p(x) then ,p(x)= kx² -√2x + 1.​

Answer 1

Step-by-step explanation:

x-1 is factor so we will take zero,

then the zero will be 1.

after then,

put value in p(x)

p(x) =kx²-√2x +1

p(x)=k(1)²-√2(1)+1

p(x)=k-√2+1

Here p(x) will be zero because we have put value of zero.

k-√2+1=0

k=√2-1

Hence the answer will be √2-1.