Question

find the value of k, if x-1 is a factor of p(x)=x²+x+k​

Answer 1

Step-by-step explanation:

Solution

if x-1 is the factor of eq which means

x-1=0 , so x= 1

putting the value of x=1 in the eq we get,

(1)²+1+k = 0

1+1+k = 0

k= -2

Answer 2

given x-1 is a factor of p(x)

x-1=0

x=1

x value in p(x)

1²+1+k=0

2+k=0

k= -2

check:-

x²+x+k=0

1²+1+(-2)=0

0=0